Find the asymptotes of the function
(x^2-4x+5)
f(x)= ---------------
x + 3
Answer: vertical asymptote is x=-3 because f(x) is not defined at that value.
If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote.![]()
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for slant/oblique asymptote divide numerator by denominator
x+3 ) x^2-4x+5 (x-7
x^2+3x
___________________
-7x+5
-7x-21
__________________
26
y= f(x) = (x-7) + 26 / (x+3)
y= x-7 is the slant/oblique asymptote.
Answer: vertical asymptote is x=-3 because f(x) is not defined at that value.
If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote.
for slant/oblique asymptote divide numerator by denominator
x+3 ) x^2-4x+5 (x-7
x^2+3x
___________________
-7x+5
-7x-21
__________________
26
y= f(x) = (x-7) + 26 / (x+3)
y= x-7 is the slant/oblique asymptote.
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